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The Asymptotic Limits of the SpatiallyAveraged Probability Distributions from the Solution to the Time-Independent Schrödinger Equation are Equal to the Time-Spent Probability Distribution from Classical Analysis |
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Consider a particle of mass m moving in space subject to a potential function V(z), such that V(0)=0, V(−z)=V(z) and V"(z)≥0 where z is the location coordinates of a point. The time-independent Schrödinger equation for the wave function φ(z) for this physical system is

where ~~h~~ is Planck's constant divided by 2π and E is the energy of the
system. It can be reduced to

where μ= (2m/~~h~~²) and K(z)=E−V(z), the kinetic energy of the system as
a function of particle location. This is an example of what the K(r) might look like.

However, in the determination of probability distributions constant factors are irrelevant because in the normalization process they cancel out. Note that the above equation may also be expressed as

This indicates that it is the variation in the energy E relative to the potential V(z) that is important. Let V(z)/E be denoted as U(z). Then instead of thinking of the issue being what happens to φ(z) as E increases without bound, it is what happens to φ(z) as U(z)→0 for all z. But first it is necessary to find a way to deal with the rapid oscillations in φ(z). Here is an example of φ²(z) for 1D space. It is for a harmonic oscillator, where V(z)=½kz².

What happens when E increases is not so much that the level of φ(z) increases but instead the density of the fluctuations increases. The range over which φ(z)² is nonzero also increases.

By eliminating the irrelevant constant factors the equation for the wave function can be reduced to

where φ²(z) must be normalized.

Consider again a particle of mass m moving in space whose position is denoted as z. The potential field given by V(z) where V(0)=0 and V(−z)=V(z). Let v be the velocity of the particle, p its momentum and E its total energy. Then

Thus

For a particle executing a periodic trajectory the time spent in an interval ds of the trajectory is ds/|v|, where |v| is the absolute value of the particle's velocity. Thus the probability density of finding the particle in that interval at a random time is

where T is the total time spent in executing a cycle of the trajectory; i.e.,
T=∫dx/|v|. It can be called the *normalization constant*, the constant
required to make the probability densities to sum to unity. This is the *time-spent*
probability distribution for the particle.
Thus

The constant factor of (m/2)^{½}/TE^{½} is irrelevant in determining
*P*(z) because it is also a factor of T and thus cancels out.

The time-spent probability distribution is thus inversely proportional to
(1−V(z)/E)^{½}, or equivalently (1−U(z))^{½}.

It is convenient for typographic reasons to represent (1−U(z)) as J(z). J(x) is proportional to kinetic energy and particle velocity
is proportional to (J(x))^{½}, as is also momentum p. Therefore the probability density function
is inversely proportional to (J(z))^{½}.

Quantum Theoretic Solution

By eliminating the irrelevant constant factors the equation determining the quantum theoretic wave function can be reduced to

or, equivalently

= − J(x)φ(x)

with, as before, J(x)=(1−U(x))

Now let λ(z) be defined by

The Laplacian ∇² of the product of two functions f·g is given by

Therefore

Note that

and

∇²(J

Since

= − λ(z)J

Therefore

= − λ(z)J

Multiplying through by J^{¼}(z) gives

+ λ(z)[−(1/4)(J

= − λ(z)J(z)

Note that

and

∇²J(z) = −∇²V(z)/E

and ∇V(z) and ∇²V(z) are fixed as E→∞. Therefore all of the terms on the LHS of the above except (∇²λ) go to zero as E increases without bound. They approach zero doubly fast because they have a derivative of J in their numerators and a power of J in their denominators. Furthermore J(z) asymptotically approaches 1 as E→∞. Thus λ(z) asymptotically approaches the solution to the equation

This is a Helmholtz equation. In two dimensions z=(r, θ) its solution is of the form

where X_{n}(r) and Y_{n}(r) are the
Bessel functions of the first and second kind, respectively, and n is a
nonnegative integer proportional to the energy E of the system.

Here are the general shapes of the Bessel functions.

The singularity of Y_{n}(z) at z=0 precludes it being a
part of λ(x)².

So the probability density λ(z)² generally consists of a function which oscillate
between relative maxima and zero values. The spatial average of that
function is a constant. Therefore the probability densities are inversely
proportional to J(x)^{½}=(1-V(x)/E)^{½}
just as the classical time-spent
probabilities are.

Here is an illustration of J(x), J(x)^{½}, and 1/J(x)^{½}
for the one dimensional case of a harmonic oscillator.

What was shown above is that the wave function that is the solution to the equation

can be factored as follows

where λ(x) is a purely oscillatory function which is asymptotically equal to the solution to a generalized Helmoltz equation.

The time-spent probability distributions are for a particle that maintains its physical existence. Thus there is no justification for the assertion by the Copenhagen Interpretation of quantum theory that particles do not have a physical existence until their characteristics are measured. In effect, the time-independent Schrödinger equation give the dynamic appearance of a physical system rather than its static appearance. The Copenhagen Interpretation treats the solurion to Schrödinger equation as if it were the static condition of the system. This is like treating the appearance of a rapidly rotating fan as if it is a unchanging translucent disk which is a single particle.

For the fundamental case of a particle moving in a potential field the spatial average of the probability densities coming from the solution of time-independent Schrödinger equation are asymptotically equal to the probability densities of the time-spent distribution from classical analysis.

There is no justification for the assertion in the Copenhagen Interpretation that particles generally do not exist materially. Effectively, except for its true believers, the Copenhagen Interpretation of quantum theory is demonstratively invalid.

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