San José State University

applet-magic.com
Thayer Watkins
Silicon Valley
& Tornado Alley
USA

The Rationality or Irrationality of
the Roots of Rational Numbers

The Unique Factorization Theorem for Integers, which is often called, The Fundamental Theorem of Arithmetic, says that any integer can be expressed as a unique product of powers of primes. Unique means that there is only one set of primes and their exponents whose product gives the integer. This theorem is proven, among other places, at Unique Factorization.

Suppose Q is a rational number expressed in its reduced form as g/h where g and h have no common factor. Then unless there exists a rational number r/s such that Q=rk/sk then Q1/k is irrational. In other words, unless Q is the ratio of two k-th powers of integers Q1/k is irrational. This takes care of proving that the irrationality of numbers such as the cube root of 3 or the fourth root of (1/2) and so forth.

Proof: Suppose Q1/k is the rational number n/m, where n and m have no common factor. The condition for Q is one of if and only if. The if part is obvious. The only if part just requires proving that the ratio of k-th powers is a reduced form.

Suppose Q is the rational number. If Q1/k then

Q = n k/mk

Since n and m have no common factor, nk and mk have no common factor. This means nk/mk is a reduced form for Q. There is only one reduced for for Q, hence nk/mk is it.

Thus if a rational number Q is not of the form n k/mk then Q1/k is irrational.

An Extention

Consider a term R of the form P1/hQ1/k where P and Q are rational numbers and h and k are positive integers. Then

Rhk = PkQh

If Rhk is not the ratio of hk powers of integers then it hk-th root, namely R, is irrational.

For example, suppose R=(2)1/3(5)1/2. Then R6 = 2253, which is equal to 4·125=500 or 500/1. Since 500 is not the sixth power of any integer, R is irrational.


HOME PAGE OF applet-magic
HOME PAGE OF Thayer Watkins