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Which are Fractional Numbers |
Consider the decimal representations of 2/7 and 3/13
These are concatenated blocks of 285714 and 230769. Some questions immediately arise, such as
Well, for starters the digit sums of 285714 and 230769 are both 9 which indicates that they are multiples of 9. Their ratios when divided by 9 are 31746 and 25641 respectively.
As to the second question consider the following:
But also
And less obviously
Note the product of the reciprocal of the fraction on the LHS with its concatenation block;
Proposition: Let (p/q) be a fraction less than or equal to 1 and K be the concatenation block. Then (q/p)K is equal to 99…99, where the number of 9's in this product is equal to m, the number digits in K.
Proof:
The equation
On the right there is the geometric series sum whose value is equal to 1/(1−1/10^{m}). Therefore
The term (10^{m}−1) is just m 9's in a row.
The concatenation block is arbitrary to a degree. For example, the concatenation block for 0.333333… could be chosen as 3, 33, 333 or any number of 3's in a row. The proposition holds for any such choice.
The product qK is equal to p(99…99). If p and q have no factor in common, q must be a factor of 99…99. But 99…99 equal to 9(11…11) so q must be a factor 9 or 11…11. For m equal to 1, q must be a factor of 9. The factors of 9 are 1, 3 and 9. So there :not be any other fractions with a denominator other than 1, 3 and 9 whose decimal representation of the concatenated block That is to say the fractions less than one and in reduced form which have a block concatenation form are 1/3, 2/3, 1/9, 2/9, 4/9, 5/9, 7/9 and 8/9.
for m equal to 2 the only integers with the property being considered are the divisors of 99 which are 1, 3, 9, 11, 33 and 99.
For m=3 the integers 1, 3 and 9 have the property but also the divisors of 111. The factorization of 111 is 3*37 so its divisors are 1, 3, 37, 111, which means that they have the property but also 333 and 999.
The factorization of 1111 is 11*101 which means its divisors are 1, 11, 101 and 1111. So the set of numbers with the property is {1, 3, 9, 11, 33, 99, 101, 1111}.
The factorization of 111111 is 3 * 7 * 11 * 13 * 37, so its divisors include 1, 3, 7, 11, 13, 21, 33, 37, 39, 77, 91, 111, 143, 231, 259, 407 , 429, 481, 777, 1001, 1221, 1443, 2849, 3003, 3367, 5291, 8547, 10101, 15873, 37037 and 111111. It becomes tedious to list all the divisors of 111111 . but it may include more besides the ones shown. The divisors of 999999 include all of the divisiors of 111111 and their multiples by 9.
The fractions (p/q) which have a concatenated m-digit block form are the such that q is a divisor of 10^{m}−1=99…99 and p is any integer which does not have a factor in common with q.
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