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One of the major enigmas of the physics of nuclei is the relatively low values of the binding energies of the small nuclides compared to that of the alpha particle. one approach to explaining the binding energies is in terms of the number of strong force interactions of the neutrons and protons in a nuclide and the number the various types of spin pairs that can be formed. The deuteron has only the neutronproton strong force interaction and the formation of the one neutronproton spin pair. The triteron has three strong force interactions; two neutronproton interactions and one neutronneutron interaction. It has one possible neutronneutron spin pair and one neutronproton spin pair. The alpha partice, on the other hand, has four neutronproton strong force interactions, one neutronneutron interaction and one protonproton interaction. There can be four possible spin pairs formed; one neutronneutron pair, one protonproton pair and two neutronproton pairs. These differences could possibly explain a deuteron having a binding energy of 2.22457 million electron volts (MeV), a triteron 8.48182 MeV and an alpha particle having a binding energy of 28.29 MeV. It would be very easy to choose values for the binding energies associated with the various interactions and spin formation that would account for the binding energy values, but those values would not necessarily be consistent with the binding energies of the other nearly three thousand nuclides.
Let the numbers of neutrons and protons be denoted by #n and #p, respectively. The number of possible neutronneutron interactions is then #n(#n1)/2 and this number will be denoted as #nn. Likewise the number of possible protonproton interactions is #p(#p1)/2 and this is denoted as #pp. The number of neutronproton interactions is #n#p. The number of neutronneutron spin pairs is #n%2; i.e., the largest integral number in the ratio #n/2 and likewise #p%2 for the proton pairs. The number of possible neutronproton spin pairs is min(#n, #p).
When the binding energies of all nuclides except the single neutron and single proton are regressed on the above six variables the result is
variable  min(n,p)  #n%2  #p%2  #np  #nn  #pp 
coefficient  10.31174  6.91730  2.15500  0.27804  0.19254  0.48958 
tratio  34.7  76.9  8.3  35.9  37.3  40.8 
The coefficient of determination (R²) reported by EXCEL for this regression is 0.99988, but this exaggerates the performance because this regression has no constant term so the unexplained variance is being compared to the average squared value of the dependent variable rather than its variance (average square deviation from the mean). The corrected R² value is 0.99935, still a very high value. The standard error of the estimate for the regression is 12.88 MeV, which is only 1.2 percent of the average binding energy. However this standard error suggest that the equation would not give an accurate estimate of the binding energy of the deuteron which is only 2.22457 MeV; and it does not. The equation prediction for the binding energy of the deuteron is 10.6 MeV. However for the alpha particle the equation estimate is 29.57 MeV, which is not bad as an estimate of 28.29 MeV. On the other hand, the equation estimate for the triteron is 17.59 MeV when the actual value is 8.48182 MeV.
While the regression equation does not give accurate estimates of the binding energies of the nuclides smaller than the alpha particle there are several very important implications of the results.
(To be continued.)
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